Question

Three particles each of mass m are kept at verticles of an equilateral triangle of side L. The gravitational field at centre due to these particle is:

• A. Zero
• B. $\frac{3GM}{L^2}$
• C. $\frac{9GM}{L^2}$
• D. $\frac{12}{\sqrt{3}}\frac{GM}{L^2}$

Answer 1

The correct option is A Zero

We know that for an equilateral triangle the line joining the center of gravity to each vertex of the triangle are each at angle ${120}^0$ and we also know that the field by each mass will be along these lines joining the center and vertex.

Also as the triangle is equilateral so all the vertex will be at same distance from the center, so the filed produced by each mass will be same.

Now as the field produced are eqaul in magnitude and at angle ${120}^0$ so

net field will be $zero.$