Question

Three particles, each of mass $M$ are placed at the three corners of an equilateral triangle of side $l$. What is the gravitational field strength at the location of $m$?

• A. $\frac{GM}{l^2}$
• B. $\frac{4GM}{l^2}$
• C. $\frac{4GM}{{3l}^2}$
• D. $\frac{GM}{{3l}^2}$

Answer 1

The correct option is C $\frac{4GM}{{3l}^2}$

Gravitational field due to two masses $M$ near mass $m$ cancel each other being equal in magnitude and opposite in direction.

Th distance between the farther mass $M$ and mass $m$ is $d=lsin{60}^{\circ }$$=\frac{\sqrt{3}l}{2}$

Hence, the field strength at $m=\frac{GM}{d^2}$$=\frac{4GM}{3l^2}$