Question

Three particles P, Q and R situated at point A on the circular path of radius 10 m. All three particle moves along the different path and reaches point B shown in figure then the ratio of distance traversed particle P and Q is:

Answer 1

Distance covered by $Q$

$d_Q=AO+OB=R+R$

$d_Q=2R$

Distance covered by $P$

$d_p=\frac{3}{4}2\pi R=\frac{3\pi R}{2}$

So, $\frac{d_p}{d_Q}=\left(\frac{3\pi }{2}R\right)/\left(2R\right)=\left(\frac{3}{4}n\right)=2.355$