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Question

Three particles with masses 10,20 and 40 g are moving with velocities 10^i,10^j and 10^km/sec respectively. If due to some interaction the first particle comes to rest and the velocity of second becomes (3^i+4^jm/sec). Then the velocity of third particle after their interaction is:

A
^i+^j+5^k
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B
^j+10^k
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C
^i+^j+10^k
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D
^i+3^j+10^k
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Solution

The correct option is D ^i+3^j+10^k
Applying conservation of linear momentum,
10×10^i+20×10^j+40×10^k=10×0+20×(3^i+4^j)+40V
V=^i+3^j+10^k

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