The correct option is
D Number of images formed by any two mirrors in the given three mirror system is equal to
5.
Let
A B and
C be the vertices of the equilateral triangle formed by three mirrors
AB ,
BC and
CA.
From the diagram we can deduce that, angle between any two mirrors is
60∘.
To find the number of images formed by any two mirror system ,
We find,
360θ=36060=6 (even number)
∴ Number of images formed by any two plane mirrors in given system ,
n=(360θ−1)=6−1=5
All these images along with the object are concylic.
For a two mirror system
AB and
BC, all images and objects lie on the periphery of a circle centred at
B and having radius
BO.
Similarly, for the system
AB and
AC.
When we draw a circles with radius
AO ,
BO and
CO. They coincide with each other at three points.
From the figure, points
4 ,
8 and
12 are the points where the images are coinciding.
⇒ Total no of images =
3× Number of images on each circle - Total number of coinciding images =
(3×5)−3=12
Hence, options (a) , (b) and (d) are the correct answers.
Caution :- Care must be taken while counting the total number of images formed by the system of 3 mirrors. |