The correct option is B 1011 J
Given that,
Charge, q1 = 1 C
Charge, q2 = 2 C
Charge, q3 = 3 C
Distance between them, r= 100 cm = 1 m
Case I: When charges are placed on the corner of triangle having side 1 m.
The potential energy of the system will be,
U1 = kr{q1q2+q2q3+q1q3}
⇒U1= k{2+6+3}
⇒U1= 11k= 11×9×109
⇒U1= 9.9×1010 J≈1011 J …(i)
Case II: When charges are moved to corner of triangle having side r′=0.5 m
The potential energy of the system will be,
U2 = kr′{q1q2+q2q3+q1q3}
⇒U2= kr′ {2+6+3}
⇒U2= k0.5 {11}
⇒U2= 2k×11=2×11×9×109
⇒U2= 19.8×1010 J≈2×1011 J…(ii)
The work done to move the charges will be,
W=U2 − U1
⇒W= (2−1)×1011 J
⇒W= 1011 J
Hence, option (a) is correct.