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Question

Three point charges 1C,2C and2C are placed at the vertices of an equilateral triangle of side 1 metre. The work done in joules by an external force to increase the separation of the charges to 2 metres is :


A
12πϵ0
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B
18πϵ0
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C
116πϵ0
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D
0
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Solution

The correct option is A 12πϵ0
Potential energy U=kq1q2r
total P.E of system =P.E.AB+P.E.AC+P.E.AC
=k(1)(2)r+k(1)(2)r+k(2)(2)r

=kr(224)

U=4kr
Now work done to separate charges W=ΔU

=U2U1

=(4kr2)(4kr1)

=1πϵ02+1πϵ01
W=12πϵ0

62046_10125_ans_29029011d7ea457496cbe68dbd9dc8c3.png

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