CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Three point charges of 3×109C are situated at each of three corners of a square, whose side is 15 cm. The magnitude and direction of the electric field at the vacant corner of the square are:

A
2130 V/m along the diagonal
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
9622 V/m along the diagonal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
22.0 V/m along the diagonal
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
zero
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2130 V/m along the diagonal
EγAB=KQr2=9×109×3×10915×102×15×102=27×104225=1.2×103 N/C
EγAC=KQr2=9×109×3×10915×102×15×102=27×104225=1.2×103 N/C
We can observe from the figure that EγABEγAC
Using parallelogram law of vector addition,
Eγr1=(EAB)2+(EAC)2=1.7×103 N/C direction along the diagonal.
For, EγAC=KQ(r)2=9×109×3×109(21×102)2=6.1×102104=6.1×102=0.61×103 N/C
Directed along the diagonal.
Therefore EγACEγr1, resultant Eγr will be given by,
Eγ=2.31×103 N/C=2130 V/m directed along the diagonal of the square.

971598_803603_ans_0c0636d9a48b494daf43ce41fb193374.png

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon