Three point charges +q,−2q and +q are placed at points (x=0,y=a,z=0),(x=0,y=0,z=0) and (x=a,y=0,z=0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are:
A
√2qa along +y direction
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√2qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
√2qa along +x direction
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B√2qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
Assemble can be treated as combination of 2 dipoles along X− axis and Y− axis repectively with dipole moment P=qa each. Net dipole moment Pnet=P^i+P^j=P√2 i.e Pnet=√2qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0) (using parallelogram law)