Three point charges +q,−2q and +q are placed at points (x=0,y=a,z=0),(x=0,y=0,z=0) and (x=a,y=0,z=0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are:
A
√2qa along +y direction
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B
√2qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
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C
qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
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D
√2qa along +x direction
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Solution
The correct option is B√2qa along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
Assemble can be treated as combination of 2 dipoles along X− axis and Y− axis repectively with dipole moment P=qa each.
Net dipole moment Pnet=P^i+P^j=P√2
i.e Pnet=√2qa
along the line joining points (x=0,y=0,z=0) and (x=a,y=a,z=0)
(using parallelogram law)