Three point masses 1kg,1.5kg,2.5kg are placed at the vertices of a triangle with sides 3cm,4cm and 5cm as shown in the figure. The location of the centre of mass with respect to the 1kg mass is:
A
0.6cm to the right of 1kg and 2cm above 1kg mass
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B
0.9cm to the right of 1kg and 2cm above 1kg mass
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C
0.9cm to the left of 1kg and 2cm above 1kg mass
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D
0.9cm to the right of 1kg and 1.5cm above 1kg mass
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Solution
The correct option is B0.9cm to the right of 1kg and 2cm above 1kg mass Assume 1kg mass as origin.
As we know, Xcm=m1×x1+m2×x2+m3×x3m1+m2+m3 ⇒Xcm=1×0+1.5×3+2.5×05=0.9cm and, Ycm=m1×y1+m2×y2+m3×y3m1+m2+m3 ⇒Ycm=1×0+1.5×0+2.5×45=2cm Hence, center of mass of the system will be 0.9cm to the right of 1kg and 2cm above 1kg mass.