wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three point masses 1 kg,1.5 kg,2.5 kg are placed at the vertices of a triangle with sides 3 cm,4 cm and 5 cm as shown in the figure. The location of the centre of mass with respect to the 1 kg mass is:


A
0.6 cm to the right of 1 kg and 2 cm above 1 kg mass
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.9 cm to the right of 1 kg and 2 cm above 1 kg mass
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0.9 cm to the left of 1 kg and 2 cm above 1 kg mass
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.9 cm to the right of 1 kg and 1.5 cm above 1 kg mass
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0.9 cm to the right of 1 kg and 2 cm above 1 kg mass
Assume 1 kg mass as origin.


As we know,
Xcm=m1×x1+m2×x2+m3×x3m1+m2+m3
Xcm=1×0+1.5×3+2.5×05=0.9 cm
and,
Ycm=m1×y1+m2×y2+m3×y3m1+m2+m3
Ycm=1×0+1.5×0+2.5×45=2 cm
Hence, center of mass of the system will be 0.9 cm to the right of 1 kg and 2 cm above 1 kg mass.

flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon