Question

Three-point particles of masses $1.0kg,1.5kg$ and $2.5kg$ are placed at three corners of a right-angle triaangle of sides $4.0cm$, $3.0cm$ and $5.0cm$ as shown in the fiigure. The center off mass of the system is at a point

• A. $0.9cm$ right and $2.0cm$ above $1kg$ mass
• B. $0.6cm$ right and $1.2cm$ above $1kg$ mass
• C. $1.5cm$ right and $1.2cm$ above $1kg$ mass
• D. $2.0cm$ right and $1.2cm$ above $1kg$ mass

Answer 1

The correct option is A $0.9cm$ right and $2.0cm$ above $1kg$ mass


Let $1kg$ as origin and $x-y$ axis as shown
$x_{cm}=\frac{1\left(0\right)+1.5\left(3\right)+2.5\left(0\right)}{5}=0.9cm$

$y_{cm}=\frac{1\left(0\right)+1.5\left(0\right)+2.5\left(4\right)}{5}=2cm$

Final Answer: $\left(b\right)$