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Question

Three points A (1, -2), B(3, 4) and C(4, 7) form:

A
a straight line
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B
an equilateral triangle
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C
a right angled triangle
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D
none of (a), (b), (c)
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Solution

The correct option is A a straight line
m1=Slope of AB=4(2)31=3and m2=Slope of BC=7443=3m1=m2
AB is parallel to BC and B is common to both AB & BC.
Hence, the point A(1, -2), B(3, 4) and C(4, 7) are collinear.

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