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Coordinate Geometry

Three points ...

Question

Three points A, B and C are collinear such that AB = 2BC. If the coordinates of the points A and B are (1, 7) and (6, -3) respectively, then the coordinates of the point C can be

(\frac{7}{2}; - 2)

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(\frac{17}{2}; - 8)

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(- \frac{17}{2}; - 8)

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(\frac{17}{2}; - 2)

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Solution

The correct option is B $(\frac{17}{2}; - 8)$
The correct answer is option (b). Check the video for the approach.

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The coordinates of two points A and B are $(- 1, 7)$ and $(4, - 3)$ . Then the coordinates of the point P on AB such that AP:PB = 2:3 are

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