Three positive numbers form an increasing G.P. If the middle term in this G.P. is doubled, the new numbers are in A.P. Then the common ratio of the G.P. is:
A
√2+√3
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B
3+√2
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C
2−√3
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D
2+√3
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Solution
The correct option is D2+√3 Let a,ar,ar2 are in G.P. Now, a,2ar,ar2 are in A.P. So, 2ar=a+ar22 ⇒r2−4r+1=0 ⇒r=4±√16−42=2±√3 As, G.P. is increasing so, r=2+√3