Question

Three rays originates from a point as shown. $\angle$AOB is ${145}^{\circ }$ and ∠AOC is ${45}^{\circ }$. Then $\angle$BOC is ___.

• A. less than ${90}^{\circ }$
• B. more than ${90}^{\circ }$
• C. ${90}^{\circ }$
• D. depends on orientation of rays.

Answer 1

The correct option is B

more than ${90}^{\circ }$

$\angle$AOB = $\angle$AOC + $\angle$BOC

or, ${145}^{\circ }$ = ${45}^{\circ }$ + x

or, x = ${100}^{\circ }$

So, the required angle is more than ${90}^{\circ }$