Three resistances 12 ohms each are connected in parallel. Three such combinations are connected in series. What is the total resistance in ohms?

12 ohms

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

16 ohms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 ohms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 ohms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A. 12 ohms.
Three resistances of 12 ohms each are connected in parallel.

Therefore the total resistance is given by,
$\frac{1}{R} = \frac{1}{12} + \frac{1}{12} + \frac{1}{12}$ $= \frac{3}{12}$
Or, R = 4 ohms

Three such combinations connected in series.

Therefore, resistance of the combination,
$R_{c o m b} = 4 + 4 + 4 = 12$ ohms.

Suggest Corrections

Similar questions

Q. Calculate equivalent resistance when three resistances of

2

ohms,

3

ohms and

6

ohms are connected in parallel combination.

Two coils have a combined resistance of 25 ohms, when connected in series and a resistance of 4 ohms when connected in parallel. What is the resistance of each coil?

Join BYJU'S Learning Program

Three resistances 12 ohms each are connected in parallel. Three such combinations are connected in series. What is the total resistance in ohms?

The correct option is A. 12 ohms.Three resistances of 12 ohms each are connected in parallel. Therefore the total resistance is given by,1R=112+112+112 =312 Or, R = 4 ohms Three such combinations connected in series. Therefore, resistance of the combination, Rcomb=4+4+4=12 ohms.