Question

Three resistances $2\Omega ,3\Omega$ and $4\Omega$ are connected in parallel. The ratio of currents passing through them when a potential difference is applied across its ends will be

• A. $6:3:2$
• B. $6:4:3$
• C. $5:4:3$
• D. $4:3:2$

Answer 1

Answer: (B)

$6:4:3$

Let $V$ be the potential difference to be applied across their ends.

Current flowing through $2\Omega$ $I_1=\frac{V}{2}$

Current flowing through $3\Omega$ $I_2=\frac{V}{3}$

Current flowing through $4\Omega$ $I_3=\frac{V}{4}$

$\therefore$ $I_1:I_2:I_3=\frac{1}{2}:\frac{1}{3}:\frac{1}{4}$

$⟹$ $I_1:I_2:I_3=6:4:3$