Question

Three resistances each of $3\Omega$ are connected as shown in figure. The resultant resistance between A and F is:

• A. $9\Omega$
• B. $2\Omega$
• C. $4\Omega$
• D. $1\Omega$

Answer 1

The correct option is D $1\Omega$

To draw the circuit bring point B to D and Point C to point E. From the diagram, inner two resistances are in parallel, and its equivalent is also parallel to the third resistance.

$\therefore R_{AF}=\frac{\frac{R}{2}\times R}{\frac{3R}{2}}$

$=\frac{R}{3}$
$\Rightarrow R_{AF}=1\Omega$