Three resistances each of 4 Ohm are connected in the form of an equilateral triangle. The effective resistance between any two corners is:

Ohm

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Ohm

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8 Ohm

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12 Ohm

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Solution

The correct option is B
Ohm

Two in series = 8 Ohm

This 8 Ohm will be parallel to 4 Ohm which gives a resultant = ( $\frac{4 \times 8}{4 + 8}) = (\frac{8}{3}) O h m$ .

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Three resistances each of 4 Ohm are connected in the form of an equilateral triangle. The effective resistance between any two corners is:

The correct option is B Ohm Two in series = 8 Ohm This 8 Ohm will be parallel to 4 Ohm which gives a resultant = (4×84+8)=(83) Ohm.

The correct option is B
Ohm

Two in series = 8 Ohm

This 8 Ohm will be parallel to 4 Ohm which gives a resultant = ( $\frac{4 \times 8}{4 + 8}) = (\frac{8}{3}) O h m$ .