Three resistances of $8 Ω, 16 Ω$ and $4 Ω$ are joined in parallel. If each resistor is rated $0.5 W$ , what is the maximum voltage that may be applied to the combination?

1 V

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1.5 V

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2 V

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2.5 V

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Solution

The correct option is B $1.5 V$
In parallel combination every component get same voltage so to find the limit we have to check that which resistance has minimum bearing voltage value.

we know $p o w e r = V^{2} / R$ power is constant $0.5 W$ so resistance having less resistance will be able to withstand very less voltage so $4 Ω$ will withstand very low voltage.

Using above formula the withstanding voltage for $4 Ω$ is $\sqrt[2]{R \times p o w e r} = \sqrt[2]{2} V o l t = 1.414 V o l t$ any voltage more than it can't be withstand by combination.
So nearest answer is B

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Three resistances of 8Ω,16Ω and 4Ω are joined in parallel. If each resistor is rated 0.5W, what is the maximum voltage that may be applied to the combination?

Three resistances of $8 Ω, 16 Ω$ and $4 Ω$ are joined in parallel. If each resistor is rated $0.5 W$ , what is the maximum voltage that may be applied to the combination?