Question

Three resistors, $2\Omega ,3\Omega$ and $6\Omega$ are connected in parallel in a circuit. The total resistance of the circuit is

• A. $1\Omega$
• B. $2\Omega$
• C. $3\Omega$
• D. $4\Omega$

Answer 1

The correct option is A

$1\Omega$

Given, $R_1=2\Omega$, $R_2=3\Omega$ and $R_3=6\Omega$.

Let the total resistance be $R_e$.

As we know, when resistors are in parallel the equivalent resistance $\frac{1}{R_e}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

So, $\frac{1}{R_e}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6}$

$\Rightarrow \frac{1}{R_e}=\frac{3+2+1}{6}=1$

$\Rightarrow R_e=1\Omega$.

Hence, the total resistance of the circuit is 1 Ω.