Three resistors are connected in series with $10 V$ supply as shown in the figure. Find the voltage drop across each resistor, and effective resistance of series combination.

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Solution

Given,
$R_{1} = 5 Ω$ , $R_{2} = 3 Ω$ , $R_{3} = 2 Ω$ , $V = 10$ Volt
Effective resistance of series combination.
$R_{s} = R_{1} + R_{2} + R_{3} = 10 Ω$
Now,
Current in Circuit $I = I = \frac{V}{R_{s}} = \frac{10}{10} = 1 A$
Voltage drop across $R_{1}$ , $V_{1} = I R_{1} = 1 \times 5 = 5 V$
Voltage drop across $R_{2}$ , $V_{2} = I R_{2} = 1 \times 3 = 3 V$
Voltage drop across $R_{3}$ , $V_{3} = I R_{3} = 1 \times 2 = 2 V$

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