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Question

Three resistors are connected in series with ideal cell of emf 62 V.Measurements are carried out by a single voltmeter.The results of measurements are VAB=VBC=VCD=20 V. Then

A
VAC=40 V
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B
VAB will be less than 40 v
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C
Resistance of voltemeter is 20R1
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D
R1=R2=R3
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Solution

The correct options are
A VAC=40 V
C Resistance of voltemeter is 20R1
D R1=R2=R3
From symmetry R1=R2=R3=R
let resistance of voltmeter be RV
then

20=iRV=(Ii)R -----(1)
and 20=622IR -----(2)
By (1) & (2)
RV=20R

than
Req=R+2R×20R22R
Req=3111R
I=6231×11=22R
VAC=I×2011R=2011×=40 V



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