Question

Three resistors are connected to a 6 V battery as shown in the figure given.

Calculate the equivalent resistance of the circuit.

Answer 1

In this circuit, $8\Omega$ and $12\Omega$ are connected in parallel, and this parallel resistors are connected in series with $7.2\Omega$.

$8\Omega$ and $12\Omega$ are in parallel, their equivalent resistance

$\frac{1}{R}=\frac{1}{8}+\frac{1}{12}=\frac{5}{24}$

$R=4.8\Omega$

Now, Equivalent resistance (series connection) of the circuit $=4.8+7.2=12\Omega$