Question

Three resistors each of $10\Omega$ are connected in series to a battery of potential difference 150 v. The current flowing through it is ..... A.

• A. 45
• B. 5
• C. 15
• D. 20

Answer 1

The correct option is B 5

$V=IR$

Current is given by,

$V=I\times R_{eq}$

$I=\frac{V}{R_{eq}}$

The three resistance are in series. So, the equivalent resistance will be:

$R_{eq}=R_1+R_2+R_3$

$R_{eq}=10+10+10$

$=30\Omega$

Substitute the values in the given formula:
$I=150/30$
$I=5$ $A$