Three rigid rods are joined to form an equilateral triangle $A B C$ of side $1 m$ . Three particles carrying charges $20 μ C$ each are attached to the vertices of the triangle. The whole system is at rest in an inertial frame. The resultant force on the charged particle at $A$ has the magnitude.

z e r o

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3.6 N

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3.6 \sqrt 3 N

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7.2 N

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Solution

The correct option is A $z e r o$
As we know
$F_{n e t} = m a$
Here
$a =$ acceleration of charge of particle at A which is zero so we can say that net force will also be zero.
$F_{n e t} = 0$

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Three rigid rods are joined to form an equilateral triangle ABC of side 1 m. Three particles carrying charges 20μ C each are attached to the vertices of the triangle. The whole system is at rest in an inertial frame. The resultant force on the charged particle at A has the magnitude.

The correct option is A zeroAs we know Fnet=maHerea=acceleration of charge of particle at A which is zero so we can say that net force will also be zero.Fnet=0

Three rigid rods are joined to form an equilateral triangle $A B C$ of side $1 m$ . Three particles carrying charges $20 μ C$ each are attached to the vertices of the triangle. The whole system is at rest in an inertial frame. The resultant force on the charged particle at $A$ has the magnitude.

The correct option is A $z e r o$
As we know
$F_{n e t} = m a$
Here
$a =$ acceleration of charge of particle at A which is zero so we can say that net force will also be zero.
$F_{n e t} = 0$