Three rings each of mass m and radius r are placed in a plane touching each other as shown. The radius of gyration of the system about the axis as shown in the figure is
A
√76r
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B
√53r
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C
√56r
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D
√72r
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Solution
The correct option is A√76r Moment of inertia of the system about the given axis, I=I1+I2+I3 I1=mr22,I2=I3=32mr2, ∴I=I1+I2+I3=72mr2 Also, moment of inertia, I = 3mk2, where k is radius of gyration. ∴3mk2=72mr2⇒k=√76r