Three rods made of same material and having the same cross-section have been joined as shown in figure. Each rod is of the same length. The ends are kept at 0∘C, 90∘C and 60∘C. The temperature of the junction of the rods will be
A
45∘C
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B
50∘C
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C
55∘C
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D
60∘C
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Solution
The correct option is B50∘C Let H1 be the heat flowing from C to B H2 be the heat flowing from D to B H be the heat flowing from B to A
As there is no heat loss
H1+H2=H
From thermal analogus of ohms law(R be thermal resistance of each rod) H1=90∘−TR H2=60∘−TR H=T−0∘R