Question

Three rods made of the same material and having the same cross-section have been joined as shown in figure. Each rod is of the same length. The left and right ends are kept at $0^{\circ }C$ and ${90}^{\circ }C$ respectively. The temperature of the junction of three

• A. ${46}^{\circ }$ C
• B. ${60}^{\circ }$ C
• C. ${30}^{\circ }$ C
• D. ${20}^{\circ }$ C

Answer 1

Answer: (B)

${60}^{\circ }$ C

$(90-V^1)=iR$

$(v^1-0)=2iR$

$\frac{90-V^1}{V^1}=\frac{1}{2}$

$180-2V^1=V^1$

$V^1=60V$

So, $T={60}^{\circ }C$