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Question

Three rods of material x and two rods of material y are connected as shown in figure. All the rods are of identical length and cross – sectional area. The end A is maintained at 100 C and the junction D at 0 C. It is given that resistance of rod of material x is R. Further, Kx=2Ky.



Match the entries of column I and column II
ColumnIColumn IIA. Temperature of junction BP. Does not behave like a balanced wheatstones bridgeB. Temperature of junction CQ. Is twice of the other.C. This network isR. 4007 degree celsiusD. Resistance of rod of material yS. 3007 degree celsius



A
A-P B-R C-P D-R
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B
A-P B-Q C-P D-R
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C
A-R B-S C-P D-Q
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D
A-Q B-Q C-Q D-P
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Solution

The correct option is C A-R B-S C-P D-Q


Thermal resistance R=lKA
If Kx=2Ky,Rx=Ry2(or)Ry=2Rx=2R
So, final diagram will be,
By the logic of current, for point B,
T1100R+T1T2R+T102R=0
2T1200+2T12T2+T1=0
5T12T2=200 (1)
For point C, (T2100)2R+(T2T1)R+(T20)R=0 5T22T1=100 (2)
Solving (1) and (2), we get,
T1=400C7 and T2=300C)7
Thermal resistance between B and D is,

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