Three rods of the same dimension have thermal conductivities 3K, 2K and K.They are arranged as shown in fig. Given below, with their ends at 100∘ C, 50∘ C and 20∘ C. The temperature of their junction is
70°C
Let the temperature of junction be θ then
according to following figure.
H = H1 + H2
⇒ 3K × A × (100 − θ)l=2KA(θ − 50)l + KA(θ − 20)l
⇒300 − 3θ = 3θ − 120 ⇒θ = 70∘C