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Question

Three rods of the same dimension have thermal conductivities 3K, 2K and K.They are arranged as shown in fig. Given below, with their ends at 100 C, 50 C and 20 C. The temperature of their junction is


A

60°C

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B

70°C

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C

50°C

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D

35°C

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Solution

The correct option is B

70°C


Let the temperature of junction be θ then

according to following figure.

H = H1 + H2

3K × A × (100 θ)l=2KA(θ 50)l + KA(θ 20)l

300 3θ = 3θ 120 θ = 70C


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