Three rods of the same mass are placed as shown in the figure. The co-ordinates of the centre of mass of the system is
A
(43,2)
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B
(53,2)
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C
(2,2)
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D
(1,12)
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Solution
The correct option is A(43,2)
As shown in figure, the centre of mass of the rods are at their respective mid points. So, (x1,y1)=(0,3), (x2,y2)=(2,3), &(x3,y3)=(2,0)
Let xcm and ycm be the co-ordinates of centre of mass of the system. Then, xcm=m1x1+m2x2+m3x3m1+m2+m3 =m(0)+m(2)+m(2)3m=43 ycm=m1y1+m2y2+m3y3m1+m2+m3 =m(3)+m(3)+m(0)3m=2 (xcm,ycm)=(43,2)