Three sides of a triangular field are 20m, 21m and 29m long respectively. The area of the field is ____.

215 m^{2}

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230 m^{2}

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210 m^{2}

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250 m^{2}

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None of these

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Solution

The correct option is C $210 m^{2}$
Here, $s = \frac{20 + 21 + 29}{2} = \frac{70}{2} = 35 m .$
$∴$ Area $= \sqrt{35 (35 - 20) (25 - 21) (35 - 29)}$
$= \sqrt{35 \times 15 \times 14 \times 6} = \sqrt{5^{2} \times 7^{2} \times 3^{2} \times 2^{2}} = 5 \times 7 \times 3 \times 2 = 210 m^{2} .$

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Three sides of a triangular field are 20m, 21m and 29m long respectively. The area of the field is ____.

The correct option is C 210m2Here, s=20+21+292=702=35m. ∴ Area =√35(35−20)(25−21)(35−29) =√35×15×14×6=√52×72×32×22=5×7×3×2=210m2.

The correct option is C $210 m^{2}$
Here, $s = \frac{20 + 21 + 29}{2} = \frac{70}{2} = 35 m .$
$∴$ Area $= \sqrt{35 (35 - 20) (25 - 21) (35 - 29)}$
$= \sqrt{35 \times 15 \times 14 \times 6} = \sqrt{5^{2} \times 7^{2} \times 3^{2} \times 2^{2}} = 5 \times 7 \times 3 \times 2 = 210 m^{2} .$