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Question

Three simple harmonic motions in the same direction having the same ampitude a and same period are superposed. If each differs in phase from the next by 45, then

A
the resultant amplitude is (1+2)a
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B
the phase of the resultant motion relative to the first is 90
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C
the energy associated with the resulting motion is (3+22) times the energy associated with any single motion
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D
the resulting motion is not simple harmonic
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Solution

The correct options are
A the resultant amplitude is (1+2)a
C the energy associated with the resulting motion is (3+22) times the energy associated with any single motion
By principle of superposition

y=y1+y2+y3

=a sin(ωt+45)+a sinωt+a sin(ωt45)

=a sin(ωt+45)+a sin(ωt45)+a sinωt

=2a sin ωt cos 45+a sin ωt

=2a sin ωt+a sin ωt=(1+2)a sin ωt

Amplitude of resultant motion =(1+2)a

b) The phase of the resultant motion relative to the first is 45.

c) Energy is SHM is proportional to square of the amplitude:
Ea2

ERE=(1+2)2a2a2 ERE=(1+2+22)1

or ER=(3+22)E

d) Resultant motion is y=(1+2)a sin ωt
It is a SHM.

Hence options (a) and (c) are correct.

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