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Question

Three simple harmonic motions in the same direction having the same amplitude A and same period are superposed. If each differs in phase from the next by 450, then

A
the resulting amplitude is (1+3)A.
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B
the resulting motion is not simple harmonic
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C
The energy associated with the resulting motion (3+22) times the energy associated with any single motion.
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D
The phase of the resultant motion relative to the first is 900
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Solution

The correct option is C The energy associated with the resulting motion (3+22) times the energy associated with any single motion.
[C] Y1=Asin(wtπ4),Y2=Asin(wt),Y3=A(sinwt+π4)
on superimposing, Resultant SHM =
Y=A[2sinwtcosπ4+sinwt]A[2sinwt+sinwt]Y=A(1+2)sinwt,ResultantAMP=(1+2)Aresultantsingle={A(1+2)}2A2Resultant=(3+22)single

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