Three simple harmonic motions in the same direction having the same amplitude A and same period are superposed. If each differs in phase from the next by 450, then
A
the resulting amplitude is (1+√3)A.
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B
the resulting motion is not simple harmonic
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C
The energy associated with the resulting motion (3+2√2) times the energy associated with any single motion.
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D
The phase of the resultant motion relative to the first is 900
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Solution
The correct option is C The energy associated with the resulting motion (3+2√2) times the energy associated with any single motion. [C] Y1=Asin(wt−π4),Y2=Asin(wt),Y3=A(sinwt+π4)