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Question

Three simple harmonic motions in the same direction having the same amplitude a and same period are superposed. If each differs in phase from the next by 45o, then.

A
The resultant amplitude (1+2)a
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B
The phase of the resultant motion relative to the first is 90o
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C
The energy associated with the resulting motion is (3+22) times the energy associated with any single motion
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D
The resulting motion is not simple harmonic
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Solution

The correct options are
A The resultant amplitude (1+2)a
C The energy associated with the resulting motion is (3+22) times the energy associated with any single motion
Let y1=asin(ωtπ4)
y2=asin(ωt)
y3=asin(ωt+π4)
On super imposing, resulting SHM-
y=a[sin(ωtπ4)+sinωt+sin(ωt+π4)]
y=a[2sinωtcosπ4+sinωt]
y=a(1+2)sinωt
Resultant amplitude =(1+2)a
Also, EresultantEsingle=(Aa)2
EresultantEsingle=(2+1)2
EresultantEsingle=(3+22)
Eresultant=(3+22)Esingle

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