Three simple harmonic motions in the same line having amplitude (a) and time period T are superposed. If each Differ in phase from the next by 45∘, then
A
the resultant motion is simple harmonic
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B
the phase of the resultant motion relative to the first is 45∘
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C
the resultant amplitude is (2+√2)a
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D
the energy associated with the resulting motion is (3+√2) times the energy associated with any single motion.
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Solution
The correct options are A the resultant motion is simple harmonic B the phase of the resultant motion relative to the first is 45∘ D the energy associated with the resulting motion is (3+√2) times the energy associated with any single motion.
Resultant amplitude : A=(a+acos45∘)√2=a(√2+1) Net energy αA2=a2(√2+1)2=(3+2√2)a2