1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three slabs of same dimension having dielectric constants K1,K2 and K3 completely fill the space between the plates of a parallel plate capacitor as shown in figure. If C is the initial capacitance of the capacitor, the new capacitance after the introduction of slabs will be:

A
(K1K2K1+K2)C
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
(K1+K2+K33)C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(K1+K2)C
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
(K1+K22)C
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

The correct option is B (K1+K2+K33)CLet the capacitance of slabs having dielectric constants K1,K2 and K3 be C1,C2 and C3 respectively. All three capacitor C1 C2 and C3 are across the same potential difference, so they are connected in parallel combination. Ceq=C1+C2+C3 Initially, C=ϵ0Ad C1=K1ε0(A3)d=K1(ε0A3d) Similarly, C2=K2(ε0A3d) C3=K3(ε0A3d) Ceq=K1(ε0A3d)+K2(ε0A3d)+K3(ε0A3d) Ceq=(K1+K2+K33)(ε0Ad) Ceqn=(K1+K2+K33)C Hence, option (b) is the correct answer.

Suggest Corrections
2
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program