Three solid cubes of sides 1cm,6cm and 8 cm are melted to form a new cube.Find the surface area of the cube so formed.

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Solution

Volume of new cube $= (1^{3} + 6^{3} + 8^{3}) {c m}^{3} = 729 {c m}^{3}$
side length of new cube $= \sqrt{729} c m = 9 c m$
Surface area of new cube $= (6 \times 9 \times 9) {c m}^{2} = 486 {c m}^{2}$

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Three solid cubes of sides 1cm,6cm and 8 cm are melted to form a new cube.Find the surface area of the cube so formed.

Volume of new cube =(13+63+83)cm3=729cm3side length of new cube =√729cm=9cmSurface area of new cube =(6×9×9)cm2=486cm2

Volume of new cube $= (1^{3} + 6^{3} + 8^{3}) {c m}^{3} = 729 {c m}^{3}$
side length of new cube $= \sqrt{729} c m = 9 c m$
Surface area of new cube $= (6 \times 9 \times 9) {c m}^{2} = 486 {c m}^{2}$