Three solid spheres, each of mass m and radius l are placed at the corners of an equilateral triangle of side 2l. The moment of inertia of this system about an axis along one of side of the triangle is ;
A
115ml2
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B
125ml2
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C
25ml2
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D
215ml2
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Solution
The correct option is D215ml2 I1=25Ml2=I2I3=25Ml2+M(x2)=25Ml2+3Ml2=175Ml2∴I=I1+I2+I3=25Ml2+25Ml2+175Ml2=215Ml2