Three sound waves of equal amplitudes have frequencies $(n - 1), n, (n + 1)$ . They superimpose to give beats. The number of beats produced per second will be

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Solution

The correct option is B 2
Net beat frequency = LCM of individual beat frequencies
= LCM of [ $(n, n - 1), (n, n + 1), (n - 1, n + 1)$ ]
= LCM of ( $1, 1, 2$ )
= $2 H z$
So, no. of beats per second = $2$

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Three sound waves of equal amplitudes have frequencies (n – 1), n, (n + 1). They superimpose to give beats. The number of beats produced per second will be

The correct option is B 2Net beat frequency = LCM of individual beat frequencies = LCM of [(n, n–1), (n, n+1), (n–1, n+1)] = LCM of (1, 1, 2) = 2 Hz So, no. of beats per second = 2

Three sound waves of equal amplitudes have frequencies $(n - 1), n, (n + 1)$ . They superimpose to give beats. The number of beats produced per second will be

The correct option is B 2
Net beat frequency = LCM of individual beat frequencies
= LCM of [ $(n, n - 1), (n, n + 1), (n - 1, n + 1)$ ]
= LCM of ( $1, 1, 2$ )
= $2 H z$
So, no. of beats per second = $2$