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Question
Three sound waves of equal amplitudes have frequencies (n – 1), n, (n + 1). They superimpose to give beats. The number of beats produced per second will be
Three sound waves of equal amplitudes have frequencies (n – 1), n, (n + 1). They superimpose to give beats. The number of beats produced per second will be
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Solution
The correct option is B 2
Net beat frequency = LCM of individual beat frequencies
= LCM of [(n, n–1), (n, n+1), (n–1, n+1)]
= LCM of (1, 1, 2)
= 2 Hz
So, no. of beats per second = 2
Net beat frequency = LCM of individual beat frequencies
= LCM of [(n, n–1), (n, n+1), (n–1, n+1)]
= LCM of (1, 1, 2)
= 2 Hz
So, no. of beats per second = 2
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