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Question

Three straight parallel current carrying conductors are shown in the figure. The force experienced by the middle conductor of length $$25 cm$$ is :

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A
Zero
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B
9×104N toward left
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C
6×104N toward left
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D
3×104N toward right
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Solution

The correct option is D $$3 \times 10^{-4} N$$ toward right
Force due to the first wire on the middle wire is,
$$F_1= \dfrac{\mu_o II_1}{6\pi} \times 25 = \dfrac{2500 \mu_o}{2\pi}$$
Force due to the second wire on the middle wire is,
$$F_2= \dfrac{\mu_o II_2}{10\pi} \times 25 = \dfrac{1000 \mu_o}{2\pi}$$
Net Force $$F = F_1-F_2= \dfrac{1500 \mu_o}{2\pi}= 3\times 10^{-4}N $$ towards right

Physics

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