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Question

Three students (A), (B) and (C) connect their two given resistors R_{1} and R_{2} in the manners shown below:

They connect the terminals marked X and Y above to the terminals marked X and Y in the circuit given below:

They record the ammeter reading (I) for different positions of the rheostat and the corresponding Voltmeter readings (V).

The average value of the ratio V/I in their observations would be minimum for :

(1) students (A) and (B) only

(2) students (B) and (C) only

(3) students (C) and (A) only

(4) student (A) only

They connect the terminals marked X and Y above to the terminals marked X and Y in the circuit given below:

They record the ammeter reading (I) for different positions of the rheostat and the corresponding Voltmeter readings (V).

The average value of the ratio V/I in their observations would be minimum for :

(1) students (A) and (B) only

(2) students (B) and (C) only

(3) students (C) and (A) only

(4) student (A) only

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Solution

According to Ohm's law, we can say that the ratio, $\frac{V}{I}=\text{Total resistance}$.

The resistors in combination made by student A are connected in parallel, while the resistors in combinations made by students B and C are connected in series. So, the total resistance between point X and Y will be minimum when the resistors are in parallel. That's why the voltage and current ratio would be minimum for student A only.

Hence, the correct answer is option 4.

The resistors in combination made by student A are connected in parallel, while the resistors in combinations made by students B and C are connected in series. So, the total resistance between point X and Y will be minimum when the resistors are in parallel. That's why the voltage and current ratio would be minimum for student A only.

Hence, the correct answer is option 4.

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