Question

Three symmetrical dice are thrown. The probability of obtaining a sum of $16$ points is

• A. $\frac{1}{6}$
• B. $\frac{1}{36}$
• C. $\frac{1}{216}$
• D. $\frac{1}{72}$

Answer 1

Answer: (B)

$\frac{1}{36}$

Obtaining the sum of $16=(4,6,6),(6,4,6),(6,6,4),(5,5,6),(5,6,5),(6,5,5)=6$
Total number $=6\times 6\times 6=216$
The probability of obtaining a sum of 16 points $=\frac{6}{216}=\frac{1}{36}$