Three tankers contain $403 l$ , $434 l$ and $465 l$ of diesel, respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of time.

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Solution

Here,

Capacities of three containers are $403 l, 434 l$ and $465 l$

Maximum measuring capacity $=$ HCF of $403, 434, 465$

Now,

$403 = 13 \times 31$

$434 = 2 \times 7 \times 31$

$465 = 3 \times 5 \times 31$

Therefore,

HCF of $403, 434, 465 = 31$
Hence, the maximum measuring capacity required is $31 l$ .

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Three tankers contain 403 l, 434 l and 465 l of diesel, respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of time.

Here, Capacities of three containers are 403 l,434 l and 465 l Maximum measuring capacity = HCF of 403,434,465 Now, 403=13×31 434=2×7×31 465=3×5×31 Therefore, HCF of 403,434,465=31 Hence, the maximum measuring capacity required is 31 l.

Three tankers contain $403 l$ , $434 l$ and $465 l$ of diesel, respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of time.