The correct option is C −30x+4y+8
Three times the sum of (5x+6y)−{7−(2x−4y)} and (5x−6y+6)= 3[(5x+6y)−{7−(2x−4y)}+(5x−6y+6)]
Simplifying the above expression,
3[(5x+6y)−{7−2x+4y}+(5x−6y+6)]
= 3(5x+6y−7+2x−4y+5x−6y+6)
= 3(12x−4y−1)
= 36x−12y−3---------(1)
Subtracting expression (1) from (6x−8y+5),
= (6x−8y+5)−(36x−12y−3)
= 6x−8y+5−36x+12y+3
= −30x+4y+8