Question

Three unbiased coins are tossed simultaneously. Find the probability of getting at least two heads.

Answer 1

$3$ coin tossed at least two heads :

$(H,H,T),(T,H,H),(H,T,H),(H,H,H)$

$=\frac{4}{8}$

$=\frac{1}{2}$

Hence, the answer is $\frac{1}{2}.$