Question

Three unbiased coins are tossed, what is probability of getting exactly two heads ?

• A. $\frac{1}{3}$
• B. $\frac{3}{4}$
• C. $\frac{2}{3}$
• D. $\frac{3}{8}$

Answer 1

The correct option is D $\frac{3}{8}$

Possible outcomes of tossing three coins are:
$\left(HHH\right),\left(HHT\right),\left(HTH\right),\left(THH\right),\left(TTT\right),\left(TTH\right),\left(THT\right),\left(HTT\right)$
here $H$ and $T$ are denoted for Head and Tail.
Total no. of outcomes $=8$
no. of outcomes with exactly two heads $=$$3$
$\therefore$ required probability = $\frac{3}{8}$
$\therefore$ Option D is correct.